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When Quinn got home, he turned the air conditioner on. T(t)T(t)T, left parenthesis, t, right parenthesis models the temperature in Quinn's home (in degrees Celsius) after ttt minutes. T(t)=42-0.7tT(t)=42?0.7tT, left parenthesis, t, right parenthesis, equals, 42, minus, 0, point, 7, t How fast did the temperature drop?

Answer :

We are given

[tex]T(t)=42-0.7t[/tex]

where

T models the temperature in Quinn's home (in degrees Celsius) after t minutes

t is time in minutes

Since, we have to find rate of change of temperature

so, we will find derivative

[tex]T'(t)=0-0.7\times 1[/tex]

[tex]T'(t)=0.7[/tex]

So, the temperature drops at a rate 0.7 degrees Celsius per minutes.........Answer

Answer: 0.7

Step-by-step explanation:

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