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the length of a rectangular deck is 5 feet longer than its width,x. the area of the deck is 310 square feet. which equation can be used to determine the width of the deck A- 0=x^2+5x-310. B- 0= 2x^2-310. C- 0=x^2-305. D- 0=x^2+5x-310

Answer :

Answer:

[tex]x^2+5x-310=0[/tex]

Step-by-step explanation:

Let's assume width of rectangular deck is x feet

so, W=x

the length of a rectangular deck is 5 feet longer than its width

so, L=x+5

we know that

area of rectangle = length*width

[tex]A=L\times W[/tex]

we can plug values

[tex]A=x\times (x+5)[/tex]

we have area =310

so, we can set A=310

[tex]x\times (x+5)=310[/tex]

[tex]x^2+5x=310[/tex]

[tex]x^2+5x-310=0[/tex]

So, equation is

[tex]x^2+5x-310=0[/tex]


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