Quadrilateral ABCD is drawn on a coordinate plane. Find the length of the side AB. Please help

Hello from MrBillDoesMath!
Answer:
sqrt(45)
Discussion:
See the attached file. The length AB is the hypotenuse of the right triangle with sides 3 and 6. Hence
AB = sqrt ( 3^2 + 6^2)
= sqrt ( 9 + 36 )
= sqrt (45) <----- this is the answer they wanted!
= sqrt (9 *5)
= sqrt(9) * sqrt(5)
= 3 * sqrt(5)
Thank you,
MrB
Answer:
B. /AB/ = [tex]\sqrt{45}[/tex] units
Step-by-step explanation:
A quadrilateral is the class of four sided figures. Examples include: squares, rectangles, rhombus, kite, parallelogram, trapezium etc.
From the graph, the quadrilateral is in the form of a trapezium.
the length of the side AB can be determined by:
Draw a perpendicular from B to meet AD at E to form triangle ABE,
From triangle ABE, AE = 3 units and BE = 6 units. Applying the Pythagoras theorem to determine the length AB, we have;
[tex]/AB/^{2}[/tex] = [tex]/BE/^{2}[/tex] + [tex]/AE/^{2}[/tex]
= [tex]6^{2}[/tex] + [tex]3^{2}[/tex]
= 36 + 9
[tex]/AB/^{2}[/tex] = 45
Find the square root of both sides,
/AB/ = [tex]\sqrt{45}[/tex]
Thus,
/AB/ = [tex]\sqrt{45}[/tex] units