someone please help! find x round to the nearest tenth! trigonometry!

Answer:
Step-by-step explanation:
Look at the picture.
Use sine:
[tex]sine=\dfrac{opposite}{hypotenuse}[/tex]
We have a measure of the angle and length of the opposite:
[tex]\alpha=28^o,\ opposite=350\ ft[/tex]
[tex]\sin28^o\approx0.4695[/tex]
Substitute:
[tex]\dfrac{350}{x}=0.4695[/tex]
[tex]\dfrac{350}{x}=\dfrac{4695}{10000}[/tex] cross multiply
[tex]4695x=3500000[/tex] divide both sides by 4695
[tex]x=\dfrac{3500000}{4695}\to x\approx745.5[/tex]