Answer :
If each guy stays in his own lane, then each one runs the
circumference of his circle.
Circumference of the lane with 50 meters radius = (2 x 50) π .
Circumference of the lane with 51 meters radius = (2 x 51) π .
The circumference of the outer lane is 2π meters greater than
the circumference of the inner lane. So the runner in the outside
lane should have a head start of 2π meters = 6.2832 meters
= 20 feet 7.4 inches.
circumference of his circle.
Circumference of the lane with 50 meters radius = (2 x 50) π .
Circumference of the lane with 51 meters radius = (2 x 51) π .
The circumference of the outer lane is 2π meters greater than
the circumference of the inner lane. So the runner in the outside
lane should have a head start of 2π meters = 6.2832 meters
= 20 feet 7.4 inches.