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A car goes 4 m/s for 10 seconds then speeds up to 12 m/s in
two seconds. The car continues at this speed for a minute. The car then
accelerates at -3 m/s" for 10 seconds
How far did the car go in each time interval?

Answer :

Explanation:

For 10 seconds, v= d/t

4= d/10

d = 4×10= 40m

For 2 seconds,

V=d/t

12 =d/2

d =12 × 2 =24m

For the last 10 seconds,

S = ut +1/2 at^2

S = 0×10 + 1/2 × - 3 ×10^2

S=-150m

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