Answered

What is the equation of the circle with a diameter of 6 units and a center located at (2, −5) on the coordinate plane? a A b B c C d D

Answer :

mberisso

Answer:

[tex](x-2)^2+(y+5)^2=36[/tex]

Step-by-step explanation:

Recall that the equation of a circle of radius R centered at [tex](x_0,y_0)[/tex] is given by:

[tex](x-x_0)^2+(y-y_0)^2=R^2[/tex]

For your particular case: R = 6, [tex]x_0[/tex] = 2, and [tex]y_0[/tex] = -5, therefore the equation becomes:

[tex](x-x_0)^2+(y-y_0)^2=R^2\\(x-2)^2+(y-(-5))^2=6^2\\(x-2)^2+(y+5)^2=36[/tex]

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