Abrsanchez02
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An ice rink is 200 feet long and 85 feet wide. The four corners of the rink are rounded to a radius of 24 feet. What is the surface area of the rink? Round the answer to the nearest square foot.

Answer :

mixter17

The surface area of the ice rink is equal to [tex]15190.44ft^{2}[/tex]

Why?

To calculate the area of the ice rink, we need to remember that the surface area of the four coners (with radius of 24 feet) is equal to the area of a single circle with a radius of 24 feet.

So, calculating the area we have:

[tex]SurfaceArea=TotalArea-CircleArea\\\\SurfaceArea=200ft*85ft-\pi *radius^{2}\\\\SurfaceArea=17000ft^{2}-\pi *(24ft)^{2}=17000ft^{2}-1809.56ft^{2}=15190.44ft^{2}[/tex]

Hence, we have that the surface area of the ice rink is equal to [tex]15190.44ft^{2}[/tex]

Have a nice day!

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