Answer :
Let the digits of number be x and y
so,
number = 10y + x
given sum of digits = 11
so,
x + y = 11 ...(1)
also,
Reversing its digits decreases the number by 27
so,
reversed number = 10x + y
according to the question,
10x + y - (10y + x) = 27
10x + y - 10y - x = 27
9x - 9y = 27
9(x - y) = 27
x - y = 3. ...(2)
(1) + (2)
x + y + x - y = 11 + 3
2x = 14
x = 14/2
x = 7
putting the value of x on (2)
x - y = 3
7 - y = 3
-y = 3 - 7
- y = -4
y = 4
x = 7
so,
number = 10y + x
= 10(4) + 7
= 40 + 7
= 47
Required number = 47
hope it helps !
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