Answer :
Answer:
mass of Fe = 4.86 g
Explanation:
Balanced chemical equation
Sb₂S₃ + 3Fe → 2Sb + 3FeS
Given data from eq.
moles of iron = 3 mol
mas of iron = ?
moles of antimony trisulfide = 1 mol
mass of antimony trisulfide = 10 g
Solution
1st we will find out the mole ratio of Sb₂S₃ and Fe from balanced chemical equation
Sb₂S₃ : Fe
1 : 3
Now we find out number of moles of citric acid Sb₂S₃ from the given mass
moles = mass / molar mass
moles = 10 g / 339.7 g/mol
moles = 0.029 mol
Now we find out moles (x) of iron needed for 0.029 mol of antimony trisulfide
from the balanced chemical equation the mole ratios are:
1 : 3
0.029 : x
Cross multiply these ratios
3 × 0.029 = 1x
0.087 = 1 x
x = 0.087 mol
Now we will find out the mass of iron
mass = moles × molar mass
mass of Fe = 0.087 mol × 55.845 g/mol
mass of Fe = 4.86 g