Answer :
Answer:
[tex]\large \boxed{\text{0.356 mol each of PbO and SO}_{2}}}[/tex]
Explanation:
2PbS + 3O₂ ⟶ 2PbO + 2SO₂
n/mol: 0.356
1. Moles of PbO
2 mol of PbO are formed from 2 mol of PbS
[tex]\text{Moles of PbO} = \text{0.356 mol PbS} \times \dfrac{\text{2 mol PbO}}{\text{2 mol PbS}} = \textbf{0.356 mol PbO}[/tex]
2. Moles of SO₂
2 mol of SO₂ are formed from 2 mol of PbS
[tex]\text{Moles of SO}_{2} = \text{0.356 mol PbS} \times \dfrac{\text{2 mol SO}_{2}}{\text{2 mol PbS}} = \textbf{0.356 mol SO}_{2}\\\\\text{The reaction produces } \large\boxed{\textbf{0.356 mol of PbO and 0.356 mol of SO}_{2}}[/tex]