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12 A box contains 5 blue balls, 3 black balls and 2
red bals of the same size. A ball is selected at
random from the box and then replaced. A second
ball is then selected Find the probability of
obtaining (a) two red balls. (b) two blue balls or
w black basic) one black ball and one red
palany order​

Answer :

R= red, B=blue, Bl=black
(a) p(R) X p(R) = 2/10 X 2/10 = 4/100 = 1/25

(b) p(B) X p(B) = 5/10 X 5/10 = 25/100
+ +
p(Bl) X p(R) =3/10 X 2/10 = 6/100 = 37/100
+ +
p(R) X p(Bl) =2/10 X 3/10 = 6/100

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