Answer :

dsdrajlin

Answer:

24.3 g

Explanation:

Let's consider the decomposition of water.

H₂O → H₂ + 0.5 O₂

We can establish the following relations.

  • At STP, 1 mole of a gas occupies a volume of 22.4 L.
  • The molar ratio of H₂O to O₂ is 1:0.5.
  • The molar mass of H₂O is 18.02 g/mol.

The mass of water required to produce 15.1 L of O₂ is:

[tex]15.1 LO_{2}\frac{1molO_{2}}{22.4LO_{2}} .\frac{1molH_{2}O}{0.5molO_{2}} .\frac{18.02gH_{2}O}{1molH_{2}O} =24.3gH_{2}O[/tex]

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