A designer is making a rectangular prism box with maximum volume, with the sum of its length, width, and height 8 in. The length must be 2

times the width. What should each dimension be? Round to the nearest tenth of an inch if necessary.

Answer :

Answer:

width = 1.8 in

length =   3.6 in

height =[tex]8-3w =8-3(1.8)= 2.6 in[/tex]

Step-by-step explanation:

A designer is making a rectangular prism box with maximum volume, with the sum of its length, width, and height 8 in

Let l , w and h are the length , width and height

[tex]l +w+h=8\\l=2w[/tex]

Plug it in the first equation

[tex]2w+w+h=8\\3w+h=8\\h=8-3w[/tex]

volume the box is length times width times height

[tex]volume = (2w)(w)(8-3w)\\16w^2-6w^3[/tex]

To get maximum volume we take derivatived

[tex]v'=32w-18w^2[/tex]

set the derivative =0 and solve for w

[tex]0=32w-18w^2\\0=-2w(9w-16)\\w=0 , w= \frac{16}{9}[/tex]

width = 1.8 in

length = 2w= 3.6 in

height =[tex]8-3w =8-3(1.8)= 2.6 in[/tex]

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