Answer :
Answer:
[tex]T=94.54N[/tex]
Explanation:
The tension in a cable is given by:
[tex]T=\mu v^2(1)[/tex]
Where [tex]\mu[/tex] is the mass density of the cable and v is the speed of the cable's pulse. These values are defined as:
[tex]\mu=\frac{m}{L}(2)\\v=\frac{d}{t}[/tex]
The pulse makes four trips down and back along the cable, so [tex]d=4(2L)[/tex]
[tex]v=\frac{8L}{t}(3)[/tex]
Replacing (2) and (3) in (1), we calculate the tension in the cable:
[tex]T=\frac{m}{L}(\frac{8L}{t})^2\\T=\frac{64mL}{t^2}\\T=\frac{64(0.21kg(3.80m))}{(0.735s)^2}\\T=94.54N[/tex]