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The thickest and strongest chamber in the human heart is the left ventricle, responsible during systole for pumping oxygenated blood through the aorta to rest of the body. Assume aortic blood starts from rest and accelerates at 22.0 m/s2 to a peak speed of 1.01 m/s.


(a) How far does the blood travel (in m) during this acceleration?

_____________ m

(b) How much time (in s) is required for the blood to reach its peak speed?

_____________s

Answer :

Answer:

(a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

Explanation:

Given that,

Acceleration = 22.0 m/s²

Speed = 1.01 m/s

(a). We need to calculate the distance

Using equation of motion

[tex]v^2=u^2+2as[/tex]

Where, v = final speed

u = initial speed

a = acceleration

s = distance

Put the value into the formula

[tex](1.01)^2=0+2\times22.0\times s[/tex]

[tex]s=\dfrac{(1.01)^2}{2\times22.0}[/tex]

[tex]s=0.0231\ m[/tex]

(b). We need to calculate the time

Using equation of motion

[tex]v =u+at[/tex]

Put the value into the formula

[tex]1.01=0+22t[/tex]

[tex]t=\dfrac{1.01}{22}[/tex]

[tex]t=0.0459\ sec[/tex]

Hence, (a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

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