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For research purposes a sonic buoy is tethered to the ocean floor and emits an infrasonic pulse of sound. The period of this sound is 68.0 ms. Determine the wavelength of the sound.

Answer :

AMB000

Answer:

[tex]\lambda=102m[/tex]

Explanation:

The relation between the period of a wave and its wavelength is [tex]v=\frac{\lambda}{T}[/tex], where v is the speed of the wave, which in our case must be the speed of sound on the ocean, which is around 1500m/s, so we can write:

[tex]\lambda=vT=(1500m/s)(0.068s)=102m[/tex]

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