Answer :

Answer:

9 and 10

Step-by-step explanation:

Consider perfect squares on either side of 92, that is

81 < 92 < 100, thus

[tex]\sqrt{81}[/tex] < [tex]\sqrt{92}[/tex] < [tex]\sqrt{100}[/tex], that is

9 < [tex]\sqrt{92}[/tex] < 10

Other Questions