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A flexible container at an initial volume of 8.15 L contains 7.51 mol of a gas. More gas is
then added to the container until it reaches a final volume of 13.9 L. Assuming the
pressure and the temperature of the gas remained constant, calculate the moles of gas
added to the container.
15.1 mol
O 5.5 mol
0 4.40 mol
12.8 mol

Answer :

The answer for the following problem is mentioned below.

  • Therefore the final moles of the gas is 12.8 moles
  • Therefore the option is "D"  (12.8 moles)

Explanation:

Given:

Initial moles ([tex]n_{1}[/tex]) = 7.51 moles

Initial volume ([tex]V_{1}[/tex]) = 8.15 L

Final volume ([tex]V_{2}[/tex]) = 13.9 L

To find:

Final moles of the gas

We know;

From the ideal gas equation;

P × V = n × R × T

where;

P represents the pressure of the gas

V represents the volume of the gas

n represents the no of moles of the gas

R represents the universal gas constant

T represents the temperature of the gas

we know;

from the above mentioned equation,

   V ∝ n

So,

[tex]\frac{V_{1} }{V_{2} }[/tex] = [tex]\frac{n_{1} }{n_{2} }[/tex]

where,

[tex]V_{1}[/tex] represents the initial volume

[tex]V_{2}[/tex] represents the final volume

[tex]n_{1}[/tex] represents the initial moles

[tex]n_{2}[/tex] represents the final moles

So,

[tex]\frac{8.15}{13.9}[/tex] = [tex]\frac{7.51}{n_{2} }[/tex]

[tex]n_{2}[/tex] = 12.8 moles

Therefore the final moles of the gas is 12.8 moles

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