To solve for x, you need to isolate/get the variable "x" by itself in the inequality:
3x - 8 ≤ 23 Add 8 on both sides
3x - 8 + 8 ≤ 23 + 8
3x ≤ 31 Divide 3 on both sides to get "x" by itself
[tex]\frac{3x}{3} \leq \frac{31}{3}[/tex]
[tex]x\leq \frac{31}{3}[/tex] (x is any number less than or equal to 31/3)
-4x + 26 ≥ 6 Subtract 26 on both sides
-4x ≥ -20 Divide -4 on both sides [When you multiply/divide by a negative number to both sides of an inequality, you flip the sign </>]
[tex]\frac{-4x}{-4} \geq \frac{-20}{-4}[/tex] (two negative signs cancel each other out and become positive)
x ≤ 5 (x is any number less than or equal to 5)