Answer :
Answer:
[H+] = 1 x 10-10 mol/L
Basic
Explanation:
pOH = -log[OH-]
= -log(1 x 10-4)
= -(-4) = 4
pOH + pH = 14
4 + pH = 14
pH = 10
Now that we know pH is 10, we can solve for the [H+]. We also now know that this is a basic solution, because the pH > 7.
pH = -log[H+]
10 = -log[H+]
[H+] = 1 x 10-10 mol/L
Answer:
The answer to your question is [H⁺] = 1 x 10⁻¹⁰ M
Explanation:
Data
[H⁺] = ?
[OH⁻] = 1 x 10⁻⁴ mol/L
Process
1.- Calculate the pOH
Formula
pOH = -log[OH⁻]
Substitution
pOH = -log [1 x 10⁻⁴]
Result
pOH = 4
2.- Calculate the pH
pH + pOH = 14
-Solve for pH
pH = 14 - pOH
-Substitution
pH = 14 - 4
-Result
pH = 10
3.- Calculate the [H⁺]
Formula
pH = -log [H⁺]
Substitution
10 = -log[H⁺]
-Solve for [H⁺]
[H⁺] = antilog (-pH)
-Substitution
[H⁺] = antilog(-10)
-Result
[H⁺] = 1 x 10⁻¹⁰ M