Answer:
Explanation:
The boy throw the pencil upward at a speed of 6.33 m/s
Then,
Initial velocity of throw is 6.33 m/s
u = 6.33 m/s.
Time to reach a maximum height of 1.25m
h = 1.25m
Note: at maximum height, the final velocity is zero
v = 0m/s
Acceleration due to gravity is
g = 9.81m/s²
We want to calculate time to reach maximum height
t = ?
Then, applying equation of motion
v = u + gt
But since it is against gravity, then, g is negaive
Then,
v = u - gt
0 = 6.33 - 9.81t
-6.33 = -9.81t
Then,
t = -6.33 / -9.81
t = 0.645 seconds
Answer:
The time you use the pencil to reach the ceiling is 0.6459 s
Explanation:
Given:
v = speed = 6.33 m/s
h = high = 1.25 m
g = gravity = 9.8 m/s²
Question: How much time does it take for the pencil to reach the ceiling, t = ?
The equation for calculate the time is:
[tex]v_{y} =v_{initial} +gt[/tex]
In this case vinitial = 0, since the pencil comes out of his hand. Solving for t:
[tex]t=\frac{v_{y} }{g} =\frac{6.33}{9.8} =0.6459s[/tex]
