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Marina had 24,500 to invest. She divided the money into three different accounts. At the end of the year, she had made RM1,300 in interest. The annual yield on each of the three accounts was 4%, 5.5%, and 6%. If the amount of money in the 4% account was four times the amount of money in the 5.5% account, how much had she placed in each account?

Answer :

geniusbrainpower1

Answer:

See below

Bold parts are important parts. They are the equations.

Marina had RM24,500 to invest.

If the amount of money in the 4% account was four times the amount of money in the 5.5% account.

" At the end of the year, she had made RM1,300 in interest. The annual yield on each of the three accounts was 4%, 5.5%, and 6%."

"If the amount of money in the 4% account was four times the amount of money in the 5.5% account,"

a = 4b

Down is the equations.

let a = amt in the 4% acct

let b = amt in the 5.5% acct

let c = amt in the 6%

"Marina had RM 24,500 to invest."

a + b + c = 24500

Replace a with 4b in both equations, simplify

b = $2000 in the 5.5% investment

a = $8000 in the 4% acct

Hope this helps.

francocanacari

Marina invested $ 8000 at 4%, $ 2000 at 5.5%, and $ 14,500 at 6%.

Since Marina had $ 24,500 to invest, and she divided the money into three different accounts, and at the end of the year, she had made $ 1,300 in interest, and the annual yield on each of the three accounts was 4%, 5.5%, and 6%, to determine, if the amount of money in the 4% account was four times the amount of money in the 5.5% account, how much had she placed in each account, the following calculation must be performed:

  • 4000 x 0.04 + 1000 x 0.055 + 19500 x 0.06 = 1385
  • 8000 x 0.04 + 2000 x 0.055 + 14500 x 0.06 = 1300

Therefore, Marina invested $ 8000 at 4%, $ 2000 at 5.5%, and $ 14,500 at 6%.

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