Answer:
Option A
Step-by-step explanation:
The first thing we want to do here is to rewrite the equation given to us, in standard circle equation -
[tex]x^2+y^2-6x+8y+21=0,\\\left(x-3\right)^2+\left(y-\left(-4\right)\right)^2=2^2[/tex]
The " standard form " of a circle is given to be in the following form,[tex](x-a)^{2} + (y-b)^{2} = r^2[/tex] where r = radius, centered at ( a, b )
Now as you can see, the center ( given by ( a, b ) ) should be ( 3, - 4 ). Respectively the radius is 2, and therefore the circle properties are -
Center [tex]( 3, - 4 )[/tex]; radius [tex]2[/tex]
Hope that helps!