Answer :
Step-by-step explanation:
Draw a right triangle with one leg value is 4 and the other leg value is 3
The triangle is attached below
To find hypotenuse , use Pythagorean theorem
[tex]c^{2} =a^{2} +b^{2} \\c^{2} =3^{2} +4^{2} \\\\c^{2} =25 \\\\c=\sqrt{25} =5[/tex]
opposite side = 4, adjacent side =3 and hypotenuse = 5
Apply trigonometric ratios
[tex]sin(A)=\frac{opposite}{hypotenuse}=\frac{4}{5}[/tex]
[tex]cos(A)=\frac{adjacent}{hypotenuse}=\frac{3}{5}[/tex]
[tex]tan(A)=\frac{opposite}{adjacent}=\frac{4}{3}[/tex]
[tex]cosec(A)=\frac{hypotenuse}{opposite}=\frac{5}{4}[/tex]
[tex]sec(A)=\frac{hypotenuse}{adjacent}=\frac{5}{3}[/tex]
[tex]cot(A)=\frac{adjacent}{opposite}=\frac{3}{4}[/tex]
