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Consider 3 trials, each having the same probability of success. Let X denote the

total number of successes in these trials. If E(X) = 1.8, the smallest possible value of Pr{X = 3}?

Construct a probability scenario that results in Pr{X = 3} having the stated value.

(Hint: For part (b), you might start by letting U be a uniform random variable on (0,1) and then defining the trials in terms of the value of U.)


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Answer :

okpalawalter8

Answer:

The smallest possible value of Pr{X = 3} is  U = 0

Step-by-step explanation:

  The number of trial is  n = 3

  The mean is  E(X) = 1.8

Gnerally given that every probability value lies between 0  and 1 ,

let U be the smallest possible value of  Pr{X = 3}

it then mean that U= 0 because in the range which probability values can take , the smallest value is  zero

So

     The smallest possible value of Pr{X = 3} is  U = 0

   

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