Answer :
Answer:
The probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.
Step-by-step explanation:
Denote the events as follows:
X = a fisher at Clearwater Park had a fishing license
Y = a fisher at Mountain View Park had a fishing license
The two events are independent.
The information provided is:
n (X) = 48
n (X') = 32
n (Y) = 72
n (Y') = 18
Then,
N (X) = n (X) + n (X')
= 48 + 32
= 80
N (Y) = n (Y) + n (Y')
= 72 + 18
= 90
Compute the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license as follows:
[tex]P(X'\cap Y)=P(X')\times P(Y)[/tex]
[tex]=\frac{n(X')}{N(X)}\times \frac{n(Y)}{N(Y)} \\\\=\frac{32}{80}\times\frac{72}{90}\\\\=0.32[/tex]
Thus, the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.