Complete Question
How much tension (Fm) must be supplied by the triceps at the elbow joint to stabilize the arm against an external force (Fe) of 200 N given [tex]dm = 2 \ cm = 0.02 \ m[/tex] and [tex]d_e = 25 \ cm = 0.25 \ cm[/tex]
Answer:
The force is [tex]F_m = 1000 \ N [/tex]
Explanation:
From the question we are told that
The external force is [tex]F_e = 200 \ N[/tex]
The length from the wrist to the elbow is [tex]d_e = 25 \ cm = 0.25 \ cm[/tex]
The length from the triceps to the elbow is [tex]dm = 2 \ cm = 0.02 \ m[/tex]
at equilibrium
Taking moment about the elbow
[tex]F_m * d_m - F_e * d_e = 0[/tex]
=> [tex]F_m * 0.02 - 200 * 0.25 = 0[/tex]
=> [tex]F_m * 0.02 - 200 * 0.25 = 0[/tex]
=> [tex]F_m = 1000 \ N [/tex]
