Answer :

ardni313

pH=2.7

Further explanation

Acetic acid = weak acid

[tex]\tt [H^+]=\sqrt{Ka.M}[/tex]

Ka = acid ionization constant

M = molarity

Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵

[tex]\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}[/tex]

[tex]\tt pH=3-log~1.998=2.7[/tex]

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