Answer :
pH=2.7
Further explanation
Acetic acid = weak acid
[tex]\tt [H^+]=\sqrt{Ka.M}[/tex]
Ka = acid ionization constant
M = molarity
Ka for Acetic acid(CH₃COOH) : 1.8 x 10⁻⁵
[tex]\tt [H^+]=\sqrt{1.8\times 10^{-5}\times 0.222}\\\\=0.001998=1.998\times 10^{-3}[/tex]
[tex]\tt pH=3-log~1.998=2.7[/tex]