Answer :
Answer:
50m; 0m/s.
Explanation:
Given the following data;
Initial velocity = 20m/s
Acceleration, a = - 4m/s²
Time, t = 5secs
To find the displacement, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting into the equation, we have;
[tex] S =20*5 + \frac{1}{2}*(-4)*5^{2}[/tex]
[tex] S =100 + (-2)*25[/tex]
[tex] S =100 - 50[/tex]
S = 50m
Next, to find the final velocity, we would use the third equation of motion;
[tex] V^{2} = U^{2} + 2aS [/tex]
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
[tex] V^{2} = 20^{2} + 2(-4)*50 [/tex]
[tex] V^{2} = 400 - 400[/tex]
[tex] V^{2} = 0[/tex]
V = 0m/s
Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.