Answer :
basically
(1,10) and (6,20) are 2 points
find the equation
y=mx+b
m=slope
b=yint
slope=(y2-y1)/(x2-x1)
slope=(20-10)/(6-1)=10/5=2
y=2x+b
find b
10=2(1)+b
10=2+b
minus 2
8=b
the equation is y=2x+8
for x=7
y=2(7)+8
y=14+8
y=22
a. g(7)=22
g(11)=
y=2(11)+8
y=22+8
y=30
b. g(11)=30
g(15)-g(10)=
2(15)-8-(2(10)-8)=
30-8-(20-8)=
22-12=
10
c g(15)-g(10)=10
a. g(7)=22
b. g(11)=30
c. g(15)-g(10)=10
(1,10) and (6,20) are 2 points
find the equation
y=mx+b
m=slope
b=yint
slope=(y2-y1)/(x2-x1)
slope=(20-10)/(6-1)=10/5=2
y=2x+b
find b
10=2(1)+b
10=2+b
minus 2
8=b
the equation is y=2x+8
for x=7
y=2(7)+8
y=14+8
y=22
a. g(7)=22
g(11)=
y=2(11)+8
y=22+8
y=30
b. g(11)=30
g(15)-g(10)=
2(15)-8-(2(10)-8)=
30-8-(20-8)=
22-12=
10
c g(15)-g(10)=10
a. g(7)=22
b. g(11)=30
c. g(15)-g(10)=10