Answer :
Answer:
2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu
Explanation:
The reactants are:
Iron = Fe
Copper (II) sulfate solution = CuSO₄
The reaction is given as:
Fe + CuSO₄ → Fe₂(SO₄)₃ + Cu
This is a single displacement reaction;
Now let us balance the equation;
aFe + bCuSO₄ → cFe₂(SO₄)₃ + dCu
Conserving Fe;
a = 2c
Conserving Cu;
b = d
Conserving S;
b = 3c
Conserving O;
4b = 12c
let b = 1;
c = [tex]\frac{1}{3}[/tex]
d = 1
a = [tex]\frac{2}{3}[/tex]
Multiply through by 3 to get whole numbers;
a = 2, b = 3, c = 1 and d = 3
2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu