Answer :
Answer:
=720000kgm/s
Explanation:
The impuse is equivalent to the rate of change of momentum which is expressed below as
Impulse= mv2 - mv1
=m(V2 - V1)
V1= initial velocity= 242 m/s
V2=final velocity= 258 m/s?
m= mass of the plane =45,000 kg
Then if we input the values, we have,
= 45000(258-242)
=720000kgm/s
Hence,the impulse on a 45,000 kg airplane is 720000kgm/s