Answer :
Answer:
Z-statistic = 1.4017 < 1.96 at 0.05 level of significance
Null hypothesis is accepted
The data suggest that the true proportion of Teen Court individuals who recidivate during the specified follow-up period differs from the proportion of Department of Juvenile Services individuals
Step-by-step explanation:
Step(i):-
Given first sample size (n₁ ) = 57
Of the 57 Teen Court individuals, 18 subsequently recidivated during the 18-month follow-up period
First sample proportion
[tex]p^{-} _{1} = \frac{x_{1} }{n_{1} } = \frac{18}{57} =0.3157[/tex]
Second sample proportion
[tex]p^{-} _{2} = \frac{x_{2} }{n_{2} } = \frac{11}{54} =0.2037[/tex]
Null Hypothesis : p₁⁻ = p₂⁻
Alternative Hypothesis : p₁⁻ ≠ p₂⁻
Step(ii):-
Test statistic
[tex]Z = \frac{p_{1} ^{-} -p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }[/tex]
where
[tex]P = \frac{n_{1}p^{-} _{1} +n_{2} p^{-} _{2} }{n_{1} +n_{2} }[/tex]
[tex]P = \frac{57 X0.3157+0.2037X54}{54+57} = 0.2612[/tex]
Q = 1 - P = 1 - 0.2612 = 0.7387
[tex]Z = \frac{0.3157-0.2037}{\sqrt{0.2612 X0.7387 (\frac{1}{57} +\frac{1}{54} )} }[/tex]
Z = 1.4017
Level of significance ∝ =0.05
The tabulated value Z₀.₀₅ = 1.96
Z-statistic = 1.4017 < 1.96 at 0.05 level of significance
Null hypothesis is accepted
The data suggest that the true proportion of Teen Court individuals who recidivate during the specified follow-up period differs from the proportion of Department of Juvenile Services individuals