Answer :
Answer:
FeCl₃ is present in excess.
Explanation:
Given data:
Number of moles of FeCl₃ = 6 mol
Number of moles of oxygen = 3 mol
Excess reactant = ?
Solution:
Chemical equation:
4FeCl₃ + 3O₂ → 2Fe₂O₃ + 6Cl₂
Now we will compare the moles of reactant with product.
FeCl₃ : Fe₂O₃
4 : 2
6 : 2/4×6= 3
FeCl₃ : Cl₂
4 : 6
6 : 6/4×6= 9
O₂ : Fe₂O₃
3 : 2
O₂ : Cl₂
3 : 6
Less number of moles of product are formed by the oxygen thus it will act as limiting reactant while FeCl₃ is present in excess.