Answer :
Answer:
Following arew the solution to this question:
Step-by-step explanation:
Build the 99% trust period of harmful chemicals for both the community, because no information is provided mostly on population standard, they just use t-test procedure to find the necessary trust period.
The confidence interval of 99 percent for both the mean community is provided by,
[tex](\bar{x} \pm t_{\frac{\alpha}{2}} \frac{s}{\sqrt{n}})[/tex]
Use Minitab as seen below to get the necessary result:
T study one: weight
Variable N Mean stDev SE Mean 99% CI
weight 6 1.883 0.417 0.170 (1.197, 2.569)
The overall population weight of a toxic material in the above output is 99 percent (1.197, 2.569).
They may say of the 99% trust interval, the 99% trust between about 1.197 mg and 2.569 mg will lie throughout the average population.
Therefore, the option (A) is valid
One of conditions would be that the overall population should be standard in attempt to discover the standard deviation. This is the true option (C).