Answer :
Answer:
Explanation:
For equilibrium ,
weight of mass 470 gram = restoring force in spring
If x be extension in spring and k be spring constant
restoring force = kx
weight of mass = kx
.47 x 9.8 = k x .36
k = 12.8 N /m.
Answer:
Explanation:
For equilibrium ,
weight of mass 470 gram = restoring force in spring
If x be extension in spring and k be spring constant
restoring force = kx
weight of mass = kx
.47 x 9.8 = k x .36
k = 12.8 N /m.