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Car A travels 20 mph faster than Car B. In the same time that Car A travels 208 mi, Car B travels 156 mi. Find their speeds. The speed of Car A is and the speed of Car B ​

Answer :

sharonkaran

Step-by-step explanation:

Assuming the speed of car B to be x and the speed of car A to be x+20

156 = 208

x. x+20

156(x+20)= 208x

156x+3120=208x

3120=208x-156x

3120=52x

x=60

The speed of car A is (x)= 60

The speed of car B is(x+20)= 80

Nayefx

Answer:

[tex]\huge\colorbox{red}{Car\: A=80}\colorbox{blue}{Car B=60}[/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • equation
  • PEMDAS

let's solve:

let the speed of car A be A

let the speed of car B be B

according to the first condition:

[tex]\quad A=B+20[/tex]

according to the second condition:

[tex]\quad 156(A)=208B[/tex]

  1. [tex]\text{substitute the value of A into the equation:}\\ \sf \implies 156(B+20)=208(B)[/tex]
  2. [tex]\sf distribute:\\ \implies 156B+3120=208B[/tex]
  3. [tex] \sf \: substract\: 156B \: from \: both \: sides : \\ \implies \: 156 B -156 B + 3120 = 208 B - 156 B \\ \implies \: 3120 = 52 B[/tex]
  4. [tex] \sf divide \: both \: sides \: by \: 52 : \\ \implies \frac{52B}{52} = \frac{3210}{52} \\ \therefore \: B = 60[/tex]

therefore

[tex]\text{the speed of car A is 60+20=80}[/tex]

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