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Using the completing-the-square method, find the vertex of the function f(x) = 5x2 + 10x + 8 and indicate whether it is a minimum or a maximum and at what point.
Maximum at (1, 8)

Minimum at (1, 8)

Maximum at (−1, 3)

Minimum at (−1, 3)

Answer :

apologiabiology
f(x)=(5x2+10x)+8
f(x)=5(x^2+2x)+8
f(x)=5(x^2+2x+1-1)+8
f(x)=5((x+1)^2-1)+8
f(x)+5(x+1)^2-5+8
f(x)=5(x+1)^2+3

for
f(x)=a(x-h)^2+k
vertex is (h,k)

we have
f(x)=5(x-(-1))^2+3
vertex is (-1,3)

minimum or max
hmm
let's evaluate another point that is not x=-1, if the y value is less than the y value of the vertex, then (-1,3) is a max
if the y value is greater than the y value of the vertex, then (-1,3) is a minimum

f(0)=0+0+8
8>3

minimum at (-1,3)

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