Answer :
Start by factoring the numerator. We know that [tex](k-5)[/tex] is a factor. So, your answer becomes:
[tex](k -5)(k^2-3k+1) / (k-5)[/tex]
Now we have two of the same terms [tex](k-5)[/tex] in the numerator and the denominator, we cancel them out and are left with:
[tex]k^2-3k+1[/tex]
[tex](k -5)(k^2-3k+1) / (k-5)[/tex]
Now we have two of the same terms [tex](k-5)[/tex] in the numerator and the denominator, we cancel them out and are left with:
[tex]k^2-3k+1[/tex]
(Kx3-16k^ + 16k-5):(k-5)
(3k-16k^+16k-5):(k-5)
(19k-16k^-5):(k-5)
19-16k^-5
K-5
When is this little signed ^ go a n and this : signifícate a división signed and in down of 19-16k^-5 go a Scratch and k-5
(3k-16k^+16k-5):(k-5)
(19k-16k^-5):(k-5)
19-16k^-5
K-5
When is this little signed ^ go a n and this : signifícate a división signed and in down of 19-16k^-5 go a Scratch and k-5