Answer :
Answer: The molarity of the sodium hydroxide solution is 1.16 M.
Explanation:
Given: [tex]V_{1}[/tex] = 35 mL, [tex]M_{1}[/tex] = 0.5 M
[tex]V_{2}[/tex] = 15 mL, [tex]M_{2}[/tex] = ?
Formula used to calculate the molarity of the sodium hydroxide solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.5 M \times 35 mL = M_{2} \times 15 mL\\M_{2} = \frac{0.5 M \times 35 mL}{15 mL}\\= 1.16 M[/tex]
Thus, we can conclude that the molarity of the sodium hydroxide solution is 1.16 M.