Answer :

DynamoPrince2612

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the concept of expo functions.

f(x) = -8(2)^x - 12 ,

for f(0) ,here substitute x = 0

so we get as ,

==> f(0) = -8(2)^0 -12

==> f(0) = -8-12

==> f(0) = -20

hence, f(0) = -20

imjusbored

Answer:

Step-by-step explanation:

If it went from f(x) ⟹ f(0), that means that x=0.

So, you would plug in 0 for x in f(x)=-8(2)^x-12.

After plugging in the value of x, x=0, into the equation, you should have

f(0)=8(2)^0-12

Now, we are solving for f(0) (or f(x)).

You would use PEMDAS to solve this:

P-PARENTHESIS

E-EXPONENT

M-MULTIPLICATION

D-DIVISION

A-ADDITION

S-SUBTRACTION

There are no parenthesis

there are exponents,

(2)^0 and that =1

so we have f(0)=8(1)-12

there is multiplication, 8(1) which =8

so now we have f(0)=8-12

there is no division

there is subtraction

8-12, which equals -4

f(0)=-4

Other Questions