Answered

What is the electric field at a point
0.300 m to the right of a
-4.77*10^-9 C charge?
Include a + or - sign to indicate the
direction of the field.

Answer :

Answer:

E = -477 N/C

Explanation:

Given that,

Charge, [tex]q=-4.77\times 10^{-9}\ C[/tex]

We need to find the electric field at a point 0.3 m to the right of the charge.

We know that the electric field at a distance r is given by :

[tex]E=\dfrac{kq}{r^2}\\\\E=\dfrac{9\times 10^9\times 4.77\times 10^{-9}}{(0.3)^2}\\\\E=-477\ N/C[/tex]

So, the electric field is -477 N/C.

Other Questions