I need help in number 13

Answer:
[tex]\huge\boxed{-0.602}[/tex]
Step-by-step explanation:
[tex]\displaystyle log (\frac{1}{4} )\\\\We \ know \ that :\\\\log (\frac{x}{y} ) = log x - log y\\\\Applying \ the \ above \ rule\\\\= log 1 - log 4\\\\Given \ that \ log \ 1 = 0 , log \ 4 = 0.602\\\\= 0 - 0.602\\\\= -0.602\\\\\rule[225]{225}{2}[/tex]
Hope this helped!