Answer :
Answer:
[tex]A= P( 1 + \frac{r}{n})^{nt}\\[/tex]
P = 1000
r = 4.5% = 0.045
n = semi annually = 2
t = 4
[tex]A= 1000( 1 + \frac{0.045}{2} )^8 =1000(1 +0.0225)^8= \$ 1194.83[/tex]
Answer:
[tex]A= P( 1 + \frac{r}{n})^{nt}\\[/tex]
P = 1000
r = 4.5% = 0.045
n = semi annually = 2
t = 4
[tex]A= 1000( 1 + \frac{0.045}{2} )^8 =1000(1 +0.0225)^8= \$ 1194.83[/tex]