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A gas has a volume of 45.0 mL and a pressure of .98 atm. If the pressure increased to 2.1 atm and the temperature remained the same, what would be the new volume?

Answer :

Answer: The new volume is 95.45 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 45.0 mL,         [tex]P_{1}[/tex] = 0.98 atm

[tex]P_{2}[/tex] = 2.1 atm,               [tex]V_{2}[/tex] = ?

According to Boyle's law, at constant temperature the pressure of a gas is inversely proportional to its volume.

Therefore, formula used to calculate the new volume is as follows.

[tex]\frac{P_{1}}{V_{1}} = \frac{P_{2}}{V_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}}{V_{1}} = \frac{P_{2}}{V_{2}}\\\frac{0.98 atm}{45.0 mL} = \frac{2.1 atm}{V_{2}}\\V_{2} = 95.45 mL[/tex]

Thus, we can conclude that the new volume is 95.45 mL.

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