Answered

Answer the following.
A bag contains, 4, green balls 3 red balls, 6 yelow and 5 pink balls. A ball is
selected at random and not relased. The ball is green. What is the probably
of selecting another green be?
Express the answer as a frection |
Engress the answer as a decimal to three deomal places
ELess this answer as a percentage to the nearest Wacle number

Answer :

Corsaquix

Answer:

[tex]\frac{3}{17}, \\0.176, \\18\%[/tex]

Step-by-step explanation:

The area a total of 4+3+6+5=18 balls, consisting of:

  • 4 green
  • 3 red
  • 6 yellow
  • 5 pink

After a green ball is selected (implied that it is not replaced or put back), there will be 17 balls total, consisting of:

  • 3 green
  • 3 red
  • 6 yellow
  • 5 pink

Therefore, the probability of drawing another green one is:

[tex]\boxed{\frac{3}{17}=0.176=18\%}[/tex]

Other Questions