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Given the equation y − 4 = three fourths(x + 8) in point-slope form, identify the equation of the same line in standard form.
−three fourthsx + y = 10
3x − 4y = −40
y = three fourthsx + 12
y = three fourthsx + 10

Answer :

You are given the equation 

[tex]y-4=\frac{3}{4}\left(x+8\right)[/tex]

What this represents is the form

[tex]\left(y-y_0\right)=m\left(x-x_0\right)[/tex]

so you can immediately read (although you are not necessarily interested in them) the y-intercept and the x-intercept. The standard form for a linear function is

[tex]y=mx+b[/tex]

So all you have to do to convert forms is to add the y-intercept to both sides and then simplify. In this case,

[tex]y=\frac{3}{4}\left(x-8\right)+4=\frac{3}{4}x-6+4=\frac{3}{4}x-2[/tex]

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