Answer :
If the order of the elements matters, we will see that there are 6,972 different possible sets, if the order does not matter, we will see that there are 3,486 possible sets.
The possible elements of the set are positive integers less than 85, then the possible elements are: 1, 2, ..., 84
So we will have a set:
{n, m}
And we know that both n and m are numbers in the interval [1, 84] (we assume that n ≠ m and that order matters.}.
For the first element, we have a total of 84 options to choose.
For the second element, we have a total of 83 options (because we selected one already).
The total number of combinations is just given by the product between the numbers of options, so we have:
C = 84*83= 6,972
There are 6,972 different possible sets.
If order does not matter, then n and m permutations are irrelevant, then the number of combinations is given by C/2:
C/2 = 6,972/2 = 3,486
In this case, there are 3,486 possible sets.
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