The period of revolution of planet "lalala65" is equal to 122 years.
Given the following data:
- Orbital radius or semi-major axis distance = 24.6 AU.
To determine the period of revolution of planet "lalala65", we would apply Kepler's third law of planetary motion:
Kepler's third law of planetary motion states that the square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis (a).
Mathematically, Kepler's third law of planetary motion is given by the formula:
[tex]P^2=a^3[/tex]
Substituting the given parameters into the formula, we have;
[tex]P^2=(24.6)^3\\\\P^2=14886.936\\\\P=\sqrt{14886.936}[/tex]
P = 122.01 ≈ 122 years.
Read more on Kepler's third law here: https://brainly.com/question/6867220
